Math round()

[zeoka]

myvalue = (“getByte” / 8) + “?”
“?” = “getByte” – ((“getByte” / 8)*8)
I believed LUA rounds automatically but this not works

a way to have (“getByte” / 8) rounded then i can substract from “getByte”

or other way ? i need that “?” = 0 to 7

• This topic was modified 10 years, 9 months ago by zeoka.

[atom]

http://lua-users.org/wiki/MathLibraryTutorial

[zeoka]

modulo !

i used it to detect a pair/unpair byte

[msepsis]

I go to the link atom provided and see:

math.modf

Return the integral and fractional parts of the given number.
> = math.modf(5)
5 0
> = math.modf(5.3)
5 0.3
> = math.modf(-5.3)
-5 -0.3
If you want the modulus (remainder), look for the modulo % operator instead.[3]

Ok. I want the remainder… where do i go to “look for the modulo % operator instead”?? I don’t understand what that’s trying to tell me.
I’ll google it but it would be helpful to get a less cryptic answer. I don’t get what this is saying…

edit: ok..i *think* i get it… per your example in the “mask to 7 bits” thread that lead me here, zeoka value%127 will mask “value” to 7 bits.

edit2: yep that did the trick – far more simple of a solution than I was expecting.

• This reply was modified 10 years, 8 months ago by msepsis.
• This reply was modified 10 years, 8 months ago by msepsis.

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